JEE Main & Advanced Sample Paper JEE Main Sample Paper-20

  • question_answer
    pH of the solution : \[\left( \begin{align}   & \text{10 }\underset{+}{\mathop{\text{litre }}}\,\text{of 0}\text{.03 N X (OH}{{\text{)}}_{2}}\,(\text{strong diacidic base)} \\  & \text{5 litre of 0}\text{.08 M HN}{{\text{O}}_{3}} \\  & \text{485 litre of 0}\text{.01 M NaN}{{\text{O}}_{3}} \\ \end{align} \right)\]

    A)  \[3.7\]                          

    B)  \[11.0\]

    C)  \[7.0\]                          

    D)  \[10.0\]

    Correct Answer: A

    Solution :

     \[{{[{{H}^{+}}]}_{remaining}}=\frac{5\times 0.08-10\times 0.03}{10+5+485}=2\times {{10}^{-4}}\] \[pH=3.7\]

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