question_answer

\[A\xrightarrow[(ii)\,{{H}^{\oplus }}]{(i)\,NaOH\,}B\xrightarrow{SOC{{l}_{2}}}C\xrightarrow[NaOH]{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}\]\[D\xrightarrow[\begin{smallmatrix}  Conc.\,{{H}_{2}}S{{O}_{4}} \\  (1\,equivalent) \end{smallmatrix}]{Conc.\,HN{{O}_{3}}}E(Major)\] E can be -

A)  

B)  

C)  

D)  

Correct Answer: B

Solution :

\[X-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}\xrightarrow[{{H}^{\oplus }}]{NaOH}X-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OH\xrightarrow{SOC{{l}_{2}}}\] \[X-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-Cl\xrightarrow{Ph-N{{H}_{2}}}X-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-NH-Ph\]