A) \[6.5\,A/rad\]
B) \[7.6\,A/rad\]
C) \[7.5\,A/rad\]
D) \[8.0\,A/rad\]
Correct Answer: B
Solution :
Here \[I=4A\] \[\theta ={{30}^{o}}={{\left( \frac{30\times \pi }{180} \right)}^{c}}=\frac{{{\pi }^{c}}}{6}\] Now, \[k=\frac{I}{\theta }=\frac{4}{\left( \frac{\pi }{6} \right)}=\frac{4\times 6\times 7}{22}=\frac{2\times 6\times 7}{11}\] \[=\frac{84}{11}=7.6A/rad\]
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