2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-20

  • question_answer
    When \[{{N}_{2}}{{O}_{5}}\]is heated at temp. T, it dissociates as \[{{N}_{2}}{{O}_{5}}(g)\rightleftharpoons {{N}_{2}}{{O}_{3}}(g)+{{O}_{2}}(g),\]\[{{K}_{c}}=2.5\] At the same time \[{{N}_{2}}{{O}_{3}}\] also decomposes as \[{{N}_{2}}{{O}_{3}}(g)\rightleftharpoons {{N}_{2}}O(g)+{{O}_{2}}(g)\]. If initially \[4.0\]moles of \[{{N}_{2}}{{O}_{5}}\] are taken in \[2.0\] litre flask and allowed to attain equilibrium, concentration of \[{{O}_{2}}\] was formed to be\[2.5M\]. Equilibrium concentration of \[{{N}_{2}}O\] is-

    A)  \[2.0\]                          

    B)  \[1.0\]

    C)  \[0.334\]                      

    D)  None of these

    Correct Answer: B

    Solution :

         \[\begin{matrix}    {} & {{N}_{2}}{{O}_{5}}(g)\rightleftharpoons {{N}_{2}}{{O}_{3}}(g)+{{O}_{2}}(g)  \\    co{{n}^{n}}\,at\,e{{q}^{m}} & 2-x\,\,x-y\,\,\,x+y  \\    {} & {{N}_{2}}{{O}_{3}}(g)\rightleftharpoons {{N}_{2}}O(g)+{{O}_{2}}(g)  \\    co{{n}^{n}}\,at\,e{{q}^{m}} & x-y\,\,y\,\,y+x  \\ \end{matrix}\] \[2.5=\frac{2.5\times (x-y)}{(2-x)}\]             \[x-y=2-x\] or \[2x-y=2\] & as per given                 \[[{{O}_{2}}(g)]=x+y=2.5\]                 \[x=1.5\] and \[[{{N}_{2}}O(g)]=y=1.0\]


You need to login to perform this action.
You will be redirected in 3 sec spinner