JEE Main & Advanced Sample Paper JEE Main Sample Paper-20

  • question_answer
    DIRECTION (Qs. 52): Read the following passage and answer the questions that follows:
    A sinusoidal wave is propagating in negative x-direction in a string stretched along x-axis. A particle of string at \[x=2m\] is found at its mean position and it is moving in positive y-direction at \[t=1\] sec. The amplitude of the wave, the wavelength and the angular frequency of the wave are \[0.1\] meter, \[\pi /2\] meter and \[2\pi \] rad/sec respectively.
    The equation of the wave is

    A)  \[y=0.1\,\sin \,(4\pi \,(t-1)+8(x-2)\]

    B)  \[y=0.1sin((t-1)-(x-2))\]

    C)  \[y=0.1sin(2\pi (t-1)+4(x-2))\]

    D)  None of these

    Correct Answer: C

    Solution :

     The equation of wave moving in negative x-direction, assuming origin of position at x = 2 and origin of time (i.e. initial time) at \[t=1\] sec. \[y=0.1\,\sin \,(2\pi t+4x)\] Shifting the origin of position to left by 2m, that is, to\[x=0\]. Also shifting the origin of time backwards by 1 sec, that is to \[t=0\]sec. \[y=0.1\,\sin \,(2\pi (t-1)\,+4(x-2))\]


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