A) \[15.1\]
B) \[30.2\]
C) \[-36.2\]
D) None of these
Correct Answer: A
Solution :
\[\frac{1}{2}{{N}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}NO(g);\] \[{{\Delta }_{f}}{{H}^{o}}=90.2\] \[{{N}_{2}}(g)+{{O}_{2}}(g)\xrightarrow{{}}2NO(g);\,\,\,{{\Delta }_{f}}{{H}^{o}}=90.2\times 2\] ?(i) \[2NO(g)+{{O}_{2}}(g)\xrightarrow{{}}2N{{O}_{2}}(g);\,\,\,{{\Delta }_{f}}{{H}^{o}}=114\] ?.(ii) \[2N{{O}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}{{N}_{2}}{{O}_{5}}(g);\] \[{{\Delta }_{f}}{{H}^{o}}=\frac{-102.6}{2}=-51.3\] ??(iii) Eq. \[(1)+(2)+(3)\] \[{{N}_{2}}(g)+\frac{5}{2}{{O}_{2}}(g)\xrightarrow{{}}{{N}_{2}}{{O}_{5}}(g)\] \[{{\Delta }_{f}}{{H}^{o}}({{N}_{2}}{{O}_{5}},g)=15.1\,kJ/mol\]You need to login to perform this action.
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