A) \[M{{R}^{2}}\]
B) \[\frac{1}{2}M{{R}^{2}}\]
C) \[\frac{1}{2}\frac{M}{{{\lambda }_{0}}}R\]
D) \[\frac{1}{\pi }\frac{M}{{{\lambda }_{0}}}R\]
Correct Answer: A
Solution :
Divide the ring into infinitely small lengths of mass \[d{{m}_{1}}.\] Even though mass distribution is non-uniform, each mass \[d{{m}_{1}}.\] is at same distance R from origin. \[\therefore \] MI o fringe bout z-axis is \[=d{{m}_{1}}{{R}^{2}}+d{{m}_{2}}{{R}^{2}}+........+d{{m}_{n}}{{R}^{2}}=M{{R}^{2}}\]You need to login to perform this action.
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