A) \[\frac{1}{2}\]
B) \[\frac{1}{\sqrt{2}}\]
C) \[\frac{\sqrt{3}}{2}\]
D) \[\frac{2}{3}\]
Correct Answer: C
Solution :
\[\frac{dy}{dx}=1-3{{x}^{2}}\,{{|}_{(-1,\,0)}}=-2\] \[\therefore \,\,a=-2\] Also (-1, 0) lies on line \[0=b-a\] \[\therefore \,\,b=-2\] \[E:\frac{{{x}^{2}}}{16}\,+\frac{{{y}^{2}}}{4}=1\] \[{{e}^{2}}=1-\frac{4}{16}\,=1-\frac{1}{4}\,=\frac{3}{4}\] \[e\frac{\sqrt{3}}{2}\]You need to login to perform this action.
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