A) \[\frac{3}{2}\]
B) \[\frac{-3}{2}\]
C) \[\frac{1}{2}\]
D) \[\frac{-1}{2}\]
Correct Answer: B
Solution :
\[\underset{x\to c}{\mathop{Lim}}\,\,\frac{f(x)-f(c)}{g(x)-g(c)}\,=\frac{f'(c)}{g'(c)}\] Now, \[f(x)\,=\frac{\pi }{2}-3{{\tan }^{-1}}x,\,\,\] in\[\left( 0,\,\frac{1}{2} \right)\] \[g(x)={{\tan }^{-1}}\,x,\,\] in \[\left( 0,\,\frac{1}{2} \right)\] \[\therefore \,\,\frac{f'(c)}{g'(c)}\,=\frac{-3}{2}\]You need to login to perform this action.
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