A) 100
B) 200
C) 500
D) 1000
Correct Answer: C
Solution :
\[D=0\] \[\left| \begin{matrix} 2 & -1 & 1 \\ 1 & -2 & 1 \\ \lambda & -1 & 2 \\ \end{matrix} \right|=0\] \[2(-4+1)\,+1(2-\lambda )\,+1(2\lambda -1)=0\] \[-6+2-\lambda +2-1=0\Rightarrow \,\lambda =5\] \[I=\int\limits_{0}^{5}{f(x)dx+\int\limits_{5}^{10}{f(x)dx}}\] Put x = 5 + t \[I=\int\limits_{0}^{5}{f(x)dx+\int\limits_{0}^{5}{f(5+t)dt}}\] \[=\int\limits_{0}^{5}{(f(x)+f(5+x)\,)dx=100\times 5=500}\]You need to login to perform this action.
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