A) A/2
B) A/16
C) A/8
D) A/6
Correct Answer: B
Solution :
Think like radioactive decay \[A'A={{e}^{-bt}}\] where b is damping factor. \[\frac{A}{4}\,=A{{e}^{-b4}}\] \[\frac{1}{4}={{e}^{-b4}}\] \[{{\left( \frac{1}{4} \right)}^{2}}\,={{\left( {{e}^{-b4}} \right)}^{2}}\] \[\left( \frac{A}{16} \right)=A\,\left( {{e}^{-b8}} \right)\]You need to login to perform this action.
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