A) 5V
B) 10V
C) 15V
D) 20V
Correct Answer: C
Solution :
\[e=L\,\frac{di}{dt}\,=5\times \,{{10}^{-3}}\,\times ({{10}^{3}})\,=5V\] Polarity of emf in inductor is developed in such a maner so that it helps to increase the existing current as it is decreasing. \[{{V}_{A}}-(5\times 1)\,+15\,+5={{V}_{B}}\] \[{{V}_{B}}-{{V}_{A}}\,=15V\]You need to login to perform this action.
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