A) \[N{{H}_{4}}CI\]
B) \[N{{H}_{4}}N{{O}_{3}}\]
C) \[AgN{{O}_{3}}\]
D) none of these
Correct Answer: D
Solution :
\[N{{H}_{4}}Cl\] gives \[N{{H}_{3}},\]\[N{{H}_{4}}N{{O}_{3}}\] gives \[{{N}_{2}}O\] and \[AgN{{O}_{3}}\] gives \[N{{O}_{2}}\]. \[(N{{H}_{4}}Cl,\,\,N{{H}_{3}}\,N{{H}_{4}}N{{O}_{3}},\,{{N}_{2}}O,\,AgN{{O}_{3}},\,N{{O}_{2}})\](1) \[N{{H}_{4}}Cl\xrightarrow{\Delta }\,N{{H}_{3}}+HCl\] (2) \[N{{H}_{4}}N{{O}_{3}}\xrightarrow{\Delta }\,{{N}_{2}}O\,+2{{H}_{2}}O\] (3) \[AgN{{O}_{3}}\,\xrightarrow{\Delta }\,Ag+N{{O}_{2}}\,+1/2{{O}_{2}}\]
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