A) 4
B) - 4
C) 6
D) - 9
Correct Answer: B
Solution :
Let the roots are r, -r and t Hence, \[r-r+t=-3\,\,\Rightarrow \,\,t=-3\] Now, product of the roots is \[(r)(-r)\,(t)\,=12\] \[-{{r}^{2}}(-3)\,=12\Rightarrow \,{{r}^{2}}=4\] Hence, roots are 2, - 2 and -3 Now, sum of the product taken two at a time is r \[(-r)+(-r)+tr=k\] \[\Rightarrow \,-4-6+6=k\Rightarrow \,-4\]You need to login to perform this action.
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