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JEE Main & Advanced Sample Paper JEE Main Sample Paper-22

  • question_answer
    The magnitude of potential energy per unit mass of the object at the surface of the earth is E and the escape velocity of the object is \[{{V}_{e}}.\] Find the correct graph.

    A)                 

    B)    

    C)                   

    D)  

    Correct Answer: B

    Solution :

    Potential energy per unit mass = E Total PE of the body = mE So, \[\frac{1}{2}\,mv_{e}^{2}\,=mE\] \[{{V}_{e}}=\sqrt{2E}\] Hence graph between \[{{v}_{e}}\] and \[\sqrt{E}\] will be straight line.


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