A) \[1.25\times {{10}^{12}}{{m}^{-3}}\]
B) \[1.25\times {{10}^{6}}{{m}^{-3}}\]
C) \[2\times {{10}^{12}}{{m}^{-3}}\]
D) \[2\times {{10}^{6}}{{m}^{-3}}\]
Correct Answer: A
Solution :
\[{{f}_{critical}}=9\times {{({{N}_{\max }})}^{1/2}}\] \[{{N}_{\max }}\,=1.25\,\times {{10}^{12}}\,{{m}^{-3}}\]You need to login to perform this action.
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