A) \[4.8\times {{10}^{-8}}\]mol \[{{L}^{-1}}{{\sec }^{-1}}\]
B) \[5.4\times \text{ }{{10}^{-5}}\] mol \[{{L}^{-1}}{{\sec }^{-1}}\]
C) \[3.6\times \text{ }{{10}^{-2}}\]mol \[{{L}^{-1}}{{\sec }^{-1}}\]
D) \[7.2\times \text{ }{{10}^{-6}}\] mol \[{{L}^{-1}}{{\sec }^{-1}}\]
Correct Answer: A
Solution :
\[Rate\,=\frac{dN{{H}_{3}}}{dt}=\frac{2d{{H}_{2}}}{3dt}\]You need to login to perform this action.
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