question_answer

Hydrocarbon \[(P)\xrightarrow[Ni]{{{H}_{2}}}(Q)\xrightarrow[hv]{C{{l}_{2}}}\]  one monochloro product only Hydrocarbon (P) can be :

(i) \[C{{H}_{3}}-C\equiv C-C{{H}_{3}}\]

(ii) \[{{(C{{H}_{3}})}_{2}}C=C{{(C{{H}_{3}})}_{2}}\]

(iii)

(iv) \[P{{h}_{2}}C=CP{{h}_{2}}\]

A)  i & ii                           

B)  ii & iii

C)  iii & iv                         

D)  i, ii, iii & iv

Correct Answer: C

Solution :

One monochloro only \[P{{h}_{2}}C=CP{{h}_{2}}\,\xrightarrow[Ni]{{{H}_{2}}}P{{h}_{2}}CH-CHP{{h}_{2}}\xrightarrow[hv]{C{{l}_{2}}}\]\[P{{h}_{2}}CH-CH(Cl)P{{h}_{2}}\]