| (i) \[C{{H}_{3}}-C\equiv C-C{{H}_{3}}\] |
| (ii) \[{{(C{{H}_{3}})}_{2}}C=C{{(C{{H}_{3}})}_{2}}\] |
(iii)  |
| (iv) \[P{{h}_{2}}C=CP{{h}_{2}}\] |
A) i & ii
B) ii & iii
C) iii & iv
D) i, ii, iii & iv
Correct Answer: C
Solution :
One monochloro only \[P{{h}_{2}}C=CP{{h}_{2}}\,\xrightarrow[Ni]{{{H}_{2}}}P{{h}_{2}}CH-CHP{{h}_{2}}\xrightarrow[hv]{C{{l}_{2}}}\]\[P{{h}_{2}}CH-CH(Cl)P{{h}_{2}}\]
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