A) \[C{{H}_{3}}C{{H}_{2}}\_\_aCl;\,\,Ph\_\_bCl(a=b)\]
B)
C)
D)
Correct Answer: C
Solution :
In \[-[NH\underline{a}\,C{{H}_{2}}-\overset{\begin{smallmatrix} O \\ \,|| \end{smallmatrix}}{\mathop{C}}\,-\overline{b}NH-C{{H}_{2}}-\overset{\begin{smallmatrix} O \\ \,|| \end{smallmatrix}}{\mathop{C}}\,]{{-}_{n}}\] lone pair of N in the bond b is delocalized so, bond length b is shorter than a.
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