JEE Main & Advanced Sample Paper JEE Main Sample Paper-22

  • question_answer
    If at \[{{27}^{o}}C\]  rate of apperance of \[{{H}_{2}}\]  (g) is \[7.2\times {{10}^{-8}}\] mole\[{{L}^{-1}}{{\sec }^{-1}}\]  than rate of reaction in mole \[{{L}^{-1}}{{\sec }^{-1}}\]  is \[N{{H}_{3}}(g)\xrightarrow{{}}\frac{1}{2}{{N}_{2}}(g)+\frac{3}{2}{{H}_{2}}(g)\]  

    A)  \[4.8\times {{10}^{-8}}\]mol \[{{L}^{-1}}{{\sec }^{-1}}\]

    B)  \[5.4\times \text{ }{{10}^{-5}}\] mol \[{{L}^{-1}}{{\sec }^{-1}}\]

    C)  \[3.6\times \text{ }{{10}^{-2}}\]mol \[{{L}^{-1}}{{\sec }^{-1}}\]

    D)  \[7.2\times \text{ }{{10}^{-6}}\] mol \[{{L}^{-1}}{{\sec }^{-1}}\]

    Correct Answer: A

    Solution :

    \[Rate\,=\frac{dN{{H}_{3}}}{dt}=\frac{2d{{H}_{2}}}{3dt}\]


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