A) \[\frac{1}{2}\]
B) \[\frac{1}{3}\]
C) \[\frac{1}{4}\]
D) \[\frac{1}{6}\]
Correct Answer: D
Solution :
\[y(x)=x-{{x}^{2}}\] and area \[=\int\limits_{0}^{1}{(x-{{x}^{2}})dx=\frac{1}{6}}\]
You need to login to perform this action.
You will be redirected in
3 sec
