A) 6
B) 9
C) 18
D) 36
Correct Answer: D
Solution :
\[|{{(adj.P)}^{-1}}=\frac{1}{|adj.P|}\,=\frac{1}{|adj.({{B}^{-1}}\,{{A}^{-1}})|}\,=\frac{1}{|{{B}^{-1}}{{A}^{-1}}{{|}^{2}}}\] \[=|{{A}^{2}}|\,\,|{{B}^{2}}|\,={{(3)}^{2}}\,\times {{(2)}^{2}}=9\times 4=36\]You need to login to perform this action.
You will be redirected in
3 sec