A) \[(-\infty ,\infty )\]
B) \[(-\infty ,1)\cup (1,\infty )\]
C) \[(0,\infty )\]
D) \[(1,\infty )\]
Correct Answer: B
Solution :
\[x\,f(x)\,=x+C\] \[\therefore \,\,f(1)=1+C\Rightarrow \,C=1\] \[\Rightarrow \,\,f(x)\,=\frac{x+1}{x}\] \[\therefore \,\,f(x)=1+\frac{1}{x};\,\,f'(x)\,=\frac{-1}{{{x}^{2}}}\] \[\Rightarrow \] f is always derivable and decreasing in its domain \[\Rightarrow \]monotonic Also f? is not bounded. The graph of \[y=f(x)\] is as shown Y = 1 and x = 0 are the two asymptotes And range is R - {1}.You need to login to perform this action.
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