A) \[\frac{1}{3}\]
B) \[\frac{2}{3}\]
C) \[\frac{4}{3}\]
D) does not exist.
Correct Answer: B
Solution :
\[k=\underset{x\to 0}{\mathop{Lim}}\,\,\frac{\int\limits_{0}^{{{x}^{2}}}{\sin \,\sqrt{x}dx}}{{{x}^{2}}}\,=\frac{2x\,\sin \,|x|}{3{{x}^{2}}}\,=\frac{2}{3}\]You need to login to perform this action.
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