A) \[VC\,{{l}_{2}}\]
B) \[VC\,{{l}_{3}}\]
C) \[VC\,{{l}_{4}}\]
D) \[VC\,{{l}_{5}}\]
Correct Answer: C
Solution :
\[\mu =1.73\,B.M\] \[\mu =\sqrt{n(n+2)}\] \[\therefore \,\,n=1\Rightarrow \] no. of unpaired \[{{e}^{-}}\] present in V is 1 \[_{23}V-................4{{s}^{2}}3{{d}^{3}}\] \[{{V}^{+4}}-...............4{{s}^{0}}3{{d}^{1}}\] \[\therefore \] the vanadium chloride has the formula \[VC{{l}_{4}}\].You need to login to perform this action.
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