A) 1 gram
B) 3 gram
C) 6 gram
D) 18 gram
Correct Answer: B
Solution :
\[(\Delta P)\]Glucose = \[(\Delta P)\]urea \[({{X}_{B}})\]Glucose = \[({{X}_{B}})\]urea \[\frac{{{\omega }_{B}}}{100}\times \frac{18}{180}\,=\frac{1}{100}\,\times \frac{18}{60}\] \[{{\omega }_{B}}=3\,\,gram\].You need to login to perform this action.
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