A) 4H
B) \[0.4\] H
C) \[0.04\]H
D) 5H
Correct Answer: C
Solution :
The induced emf is \[e=-L\,\frac{di}{dt}\] Here \[di=(2-10)A=-8A,\,\,dt=0.1\,s\] and \[e=3.28\,V\] \[\therefore \,\,3.28\,=-\frac{L(-8)}{0.1}\] \[\Rightarrow \,L=-\frac{3.28\,\times 0.1}{8}=0.04H\]You need to login to perform this action.
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