A) \[0.5\] s
B) 1 s
C) \[\sqrt{\frac{2}{3}}\] s
D) 2 s
Correct Answer: B
Solution :
Tension in the string \[T-mg\,=30\times 10\,=300\,N\] T - Mg = Ma From the figure, 300-10 x 10= 10a \[a=20\,m{{s}^{-2}}\] Thus, the maximum acceleration with which the stone can be raised is 20 ms~2. Given, s = 10m and u = 0 \[10=\frac{1}{2}\,(20)\,{{t}^{2}}\Rightarrow \,t=1\,s\]You need to login to perform this action.
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