A) 50 J
B) 100J
C) \[5\times {{10}^{2}}\] J
D) 200 J
Correct Answer: A
Solution :
From work energy theorem Work done by all forces = Change in kinetic energy \[{{W}_{F}}+{{W}_{mg}}\,={{K}_{f}}\,-{{K}_{i}}\] \[18\times 5+(1\times 10)\,(-4)\,={{K}_{f}}\] \[90-40\,={{K}_{f}}\,\Rightarrow \,{{K}_{f}}=50\,J\]You need to login to perform this action.
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