A)
B)
C)
D)
Correct Answer: B
Solution :
\[{{E}_{Z{{n}^{2+}}|Zn}}\,=E_{Z{{n}^{2+}}|Zn}^{o}\,-\frac{0.059}{2}\,\log \,[Z{{n}^{+2}}]\]Comparing with \[y=mx+c,\] graph between \[{{E}_{z{{n}^{2+}}|Zn}}\] and \[\log [Z{{n}^{2+}}]\] is a straight line with positive slope and positive intercept.You need to login to perform this action.
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