A) \[x({{x}^{2}}+{{y}^{2}})=a{{y}^{2}}=0\]
B) \[y({{x}^{2}}+{{y}^{2}})=a{{x}^{2}}=0\]
C) \[x({{x}^{2}}-{{y}^{2}})+a{{y}^{2}}=0\]
D) \[{{x}^{2}}+{{y}^{2}}+a{{y}^{2}}=0\]
Correct Answer: A
Solution :
Tangent \[y=mx+\frac{a}{m}\] Line through origin and perpendicular to it is x + my = 0 = 0. Now eliminate m.You need to login to perform this action.
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