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JEE Main & Advanced Sample Paper JEE Main Sample Paper-24

  • question_answer
    In Young?s double slit experiment (slit distance d) monochromatic light of wavelength \[\lambda \], is used and the fringe pattern observed at a distance L from the slits. The angular position of the bright fringes are

    A)  \[{{\sin }^{-1}}\left( \frac{n\lambda }{d} \right)\]                      

    B)  \[{{\sin }^{-1}}\left( \frac{n+\frac{1}{2}\lambda }{d} \right)\]

    C)  \[{{\sin }^{-1}}\left( \frac{n\lambda }{L} \right)\]          

    D)  \[{{\sin }^{-1}}\left( \frac{\left( n+\frac{1}{2} \right)\lambda }{L} \right)\]

    Correct Answer: A

    Solution :

    For constructive interference Path difference, A x= d sin \[\Delta \,x=d\,\sin \,\theta =n\lambda \] \[\Rightarrow \,\,\theta ={{\sin }^{-1}}\,\left( \frac{n\lambda }{d} \right)\]


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