A) 25 cal
B) 14 cal
C) 10 cal
D) 20 cal
Correct Answer: A
Solution :
Voltage across parallel combination is same. The equivalent resistance of upper branch \[R=4+6=10\Omega \] So, \[{{i}_{1}}\times 10={{i}_{2}}\times 10\,\,or\,\,{{i}_{2}}={{i}_{2}}=i\]i.e. same current is flowing through both branches. Now, it is given that \[{{H}_{4\Omega }}\,=10\,\,cal\,\,or\,\,{{i}^{2}}\,\,t\times 4=10\,\,or\,\,{{i}^{2}}t=\frac{10}{5}\] \[{{H}_{4\Omega }}\,=10\times {{i}^{2}}t=\,\frac{10\times 10}{4}\,=25\,cal\]
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