A) The charge on the capacitor
B) The stored energy in the capacitor
C) The potential difference between the plates.
D) the electric field in the capacitor.
Correct Answer: A
Solution :
If a dielectric slab between the plates of a charged capacitor, the intensity of electric field, potential difference of capacitor and the energy stored all reduce to \[\frac{1}{K}\] times and capacity of the capacitor increases K times. But the charge on the capacitor remains unchanged Here, K is the dielectric constant.
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