JEE Main & Advanced
Sample Paper
JEE Main Sample Paper-24
question_answer
A body thrown vertically up to reach its maximum height in t second, the total time from the time of projection to reach a point at half of its maximum height while returning (in sec) is:
A) \[\sqrt{2}\,t\]
B) \[\left( 1+\frac{1}{\sqrt{2}} \right)t\]
C) \[\frac{3\,t}{2}\]
D) \[\frac{t}{\sqrt{2}}\]
Correct Answer:
B
Solution :
\[t'\,\sqrt{\frac{2\left( \frac{h}{2} \right)}{g}}=\,\,\sqrt{\frac{h}{g}}=\,\sqrt{\left( \frac{\frac{1}{2}g{{t}^{2}}}{g} \right)}\,=\frac{t}{\sqrt{2}}\] Required time \[=t+t'\,=t+\frac{t}{\sqrt{2}}=t\left( 1+\frac{1}{\sqrt{2}} \right)\]