A) \[9.08\]
B) \[9.43\]
C) \[11.72\]
D) \[8.73\]
Correct Answer: B
Solution :
\[[N{{H}_{3}}]=0.3\,M\,\,\,\,\,\,[NH_{4}^{+}]\,=0.2M\] \[{{K}_{b}}\,=1.8\times {{10}^{-5}}\] \[{{p}^{OH}}\,=p{{k}_{b}}\,+\log \,\frac{[salt]}{[base]}\,=4.74\,+\log \,\frac{0.2}{0.3}\]You need to login to perform this action.
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