A) 9
B) 24
C) 40
D) 87
Correct Answer: B
Solution :
\[M+{{H}_{2}}S{{O}_{4}}\xrightarrow{\,}\,MS{{O}_{4}}+{{H}_{2}}\] \[\frac{mole\,of\,M}{1}\,=\frac{Mole\,of\,{{H}_{2}}S{{O}_{4}}}{1}\] \[\frac{1}{a}\,=\frac{4.08}{98}\] \[a=\frac{98}{4.08}=24.01\] This is atomic weight of M (M) = 24.You need to login to perform this action.
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