JEE Main & Advanced
Sample Paper
JEE Main Sample Paper-24
question_answer
The distance of the plane passing through the point P (1, 1, 1) and perpendicular to the line \[\frac{x-1}{3}=\frac{y-1}{0}=\frac{z-1}{4}\] from the origin is
A) \[\frac{3}{4}\]
B) \[\frac{4}{3}\]
C) \[\frac{7}{5}\]
D) 1
Correct Answer:
C
Solution :
Equation of the plane is \[A(x-1)+B(y-1)\,+C(z-1)=0\] Since the line is perpendicular to the plane (1) \[\therefore \,3(x-1)\,+0(y-1)\,+4(z-1)=0\] \[\Rightarrow \,\,3x+0y\,+4z-7=0\] \[\therefore \] Distance from (0, 0, 0) \[d=\,\left| \frac{-7}{5} \right|=\frac{7}{5}\]