A) \[{{H}_{2}}Po<{{H}_{2}}Te<{{H}_{2}}Se<{{H}_{2}}S<{{H}_{2}}O\]
B) \[{{H}_{2}}Po<{{H}_{2}}O<{{H}_{2}}Te<{{H}_{2}}Se<{{H}_{2}}S\]
C) \[{{H}_{2}}S<{{H}_{2}}O<{{H}_{2}}Te<{{H}_{2}}Se<{{H}_{2}}Po\]
D) \[{{H}_{2}}O<{{H}_{2}}S<{{H}_{2}}Te<{{H}_{2}}Se<{{H}_{2}}Po\]
Correct Answer: A
Solution :
Down the group bond \[(H-E)\] dissociation enthalpy decreases as (H ? E) bond length increases and thus thermal stability of hydrides also decreases.
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