A) \[y=x+1\]
B) \[y=x+2\]
C) \[y=x-2\]
D) \[y=-x-2\]
Correct Answer: D
Solution :
Tangent to parabola is \[y=mx+\frac{2}{m}\] If it is also tangent to circle \[\therefore \,\left| \,\frac{2/m}{\sqrt{1+{{m}^{2}}}} \right|=\sqrt{2}\Rightarrow \,m=\pm \,1\] \[\therefore \,\] Equation of tangent is \[\therefore \,\] \[y=x+2\]or \[y=-x-2\] \[\therefore \,\] Tangent below x-axis is \[y=-x-2\]You need to login to perform this action.
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