A) \[{{2}^{9}}\]
B) \[{{2}^{8}}\]
C) \[{{2}^{7}}\]
D) \[{{2}^{6}}\]
Correct Answer: D
Solution :
\[n(A)=3\] \[\therefore \] Total number of relation in \[\text{set}\,A={{2}^{3\times 3}}={{2}^{9}}\]and maximum number of Cartesian product = 9 out of which 3 ordered pair is necessary for reflexive. So, for remaining 6 ordered pair Number of ordered pair required = \[^{6}{{C}_{0}}{{+}^{6}}{{C}_{1}}{{+}^{6}}{{C}_{2}}+{{....}^{6}}{{C}_{6}}={{2}^{6}}\]
You need to login to perform this action.
You will be redirected in
3 sec
