A) \[-1\]
B) \[-2\]
C) \[-3\]
D) \[-4\]
Correct Answer: B
Solution :
The midpoint of the segment is \[\left( \frac{2-4}{2},\,\frac{3+1}{2},\,\frac{2+4}{2} \right)\] = (-1, 2, 3) and the vector between this point and (-3, 6, 1) is <-1-(-3), 2 - 6, 3-1 > and<2,-4,2>. \[\therefore \]the line has parametric equations x=-3+2t, y = 6 - 4t and z =1 + 2t. Solving each of these equations for t and setting the expressions equal makes the equation. \[\frac{x+3}{a}=\frac{y-6}{b}=\frac{z-1}{c}\] \[\Rightarrow \,\frac{x+3}{1}=\frac{y-6}{-2}\,=\frac{z-6}{1}\] So 1(-2)-1-(1-2+1)= - 2You need to login to perform this action.
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