A) \[\frac{n}{n+1}\]
B) \[\frac{n-1}{n+1}\]
C) \[\frac{1}{n+1}\]
D) \[\frac{1}{n-1}\]
Correct Answer: C
Solution :
\[P({{\overline{A}}_{i}})=1-\frac{1}{i+1}=\frac{i}{i+1}\]P (none of event occur) \[P({{\overline{A}}_{i}})\,P({{\overline{A}}_{2}}).....P({{\overline{A}}_{n}})\,=\frac{1}{2}\,\times \frac{2}{3}.........\frac{n}{n+1}\,=\frac{1}{n+1}\]You need to login to perform this action.
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