A) \[\frac{2xy}{2y-{{x}^{2}}}\]
B) \[\frac{xy}{2y-{{x}^{2}}}\]
C) \[\frac{xy}{y-{{x}^{2}}}\]
D) \[\frac{2xy}{2+\frac{{{x}^{2}}}{y}}\]
Correct Answer: A
Solution :
\[y={{x}^{2}}+\frac{1}{y}\Rightarrow \,\frac{dy}{dx}=\frac{2xy}{2y-{{x}^{2}}}\]You need to login to perform this action.
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