A) 43200
B) 432
C) 72
D) 7.2
Correct Answer: D
Solution :
Work done by the gun = Total kinetic energy of the Bullets \[=n\times \frac{1}{2}m{{v}^{2}}=240\times \frac{1}{2}\times 10\times {{10}^{-3}}{{(600)}^{2}}\] \[=\text{ }120\times 10\times {{10}^{-3}}\times 600\times 600\] \[Power\,of\,gun=\frac{Work\,done}{Time\,Taken}\] \[=\frac{120\times 10\times {{10}^{-3}}\times 600\times 600}{l\,\min }\] \[=\frac{120\times 10\times 360}{60}=120\times 10\times 6W\] \[=\frac{120\times 10\times 6}{1000}kW=7.2kW\]
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