A) \[\sqrt{\frac{2b}{a}}\]
B) \[\sqrt{\frac{a}{2b}}\]
C) \[\sqrt{\frac{a}{b}}\]
D) \[\sqrt{\frac{b}{a}}\]
Correct Answer: B
Solution :
At origin acceleration a is centripetal acceleration v is along the tangent along x axis. Hence dy/dx=2bxYou need to login to perform this action.
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