A) 36
B) 24
C) 18
D) 9
Correct Answer: C
Solution :
Equation of projectile \[y=10x-\left( \frac{5}{9} \right){{x}^{2}}\] Standard equation \[y=x\tan \theta -\,\frac{g}{2{{u}^{2}}{{\cos }^{2}}\theta }.{{x}^{2}}\] On comparing, we get \[\tan \theta =10\] and \[\frac{g}{2{{u}^{2}}\,{{\cos }^{2}}\theta }\,\,=\frac{5}{9}\] \[{{u}^{2}}{{\cos }^{2}}\theta =9\,\,or\,\,g=10\,m{{s}^{-2}}\] Range of projectile \[R=\frac{2{{u}^{2}}\sin \theta \cos \theta }{g}=\frac{2{{u}^{2}}\,\tan \theta .\,{{\cos }^{2}}\theta }{g}\]\[=\frac{2({{u}^{2}}{{\cos }^{2}}\theta )\tan \theta }{g}\,=\frac{2\times 9\times 10}{10}\,=18\,m\]
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