A) \[25\times {{10}^{-6}}C\]
B) \[2\times {{10}^{-6}}C\]
C) \[{{10}^{-6}}C\]
D) \[8\times {{10}^{-6}}C\]
Correct Answer: A
Solution :
\[B=0.5\,T,\,\,{{A}_{1}}=101\,c{{m}^{2}}\,=101\,\times {{10}^{-4}}\,{{m}^{2}}\] \[R=2\Omega \] Amount of charge \[=q=\frac{B\Delta A}{R}\] \[=\frac{0.5\times \,(101\,\times {{10}^{-4}}-100\,\times {{10}^{-4}})}{2}\] \[=\frac{0.5\,\times 1\times {{10}^{-4}}}{2}=2.5\,\times {{10}^{-6}}C\]You need to login to perform this action.
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