A) \[0.500\] V
B) \[0.325\] V
C) \[0.650\] V
D) \[0.150\] V
Correct Answer: B
Solution :
\[C{{u}^{2+}}+1{{e}^{-}}\to \,C{{u}^{+}}\,\,\,\,E_{1}^{0}\,=0.15v\,\,\Delta G_{1}^{0}\,=-{{n}_{1}}E_{1}^{0}F\] \[C{{u}^{+}}+1{{e}^{-}}\to \,Cu\,\,\,\,E_{2}^{0}\,=0.50v\,\,\Delta G_{2}^{0}\,=-{{n}_{2}}E_{2}^{0}F\]____________________________________ \[C{{u}^{+}}\,+1{{e}^{-}}\,\to Cu\,\,\Delta {{G}^{o}}=\Delta G_{1}^{o}\,\,+\Delta G_{2}^{o}\] \[(-1)\,n\,{{E}^{o}}\,F=(-1)\,n,\,\,E_{1}^{0}\,F+(-1){{n}_{2}}E_{2}^{0}F\] \[{{E}^{0}}=\frac{{{n}_{1}}E_{1}^{0}\,+{{n}_{2}}E_{2}^{0}}{n}\,=\frac{0.15\times 1+0.50\times 1}{2}=0.325\,V\]
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