JEE Main & Advanced Sample Paper JEE Main Sample Paper-25

  • question_answer
    In the synthesis of sodium carbonate by Solvay (or ammonia soda) process the recovery of ammonia is done by treating \[N{{H}_{4}}C\ell \] with\[Ca{{(OH)}_{2}}\]. The by product obtained in this process is

    A)  \[CaC{{\ell }_{2}}\]                             

    B)  \[NaC\ell \]

    C)  NaOH                         

    D)  \[NaHC{{O}_{3}}\]

    Correct Answer: A

    Solution :

    \[N{{H}_{3}}+C{{O}_{2}}+{{H}_{2}}O\,\xrightarrow{\,}\,N{{H}_{4}}HC{{O}_{3}}\] \[NaC\ell +N{{H}_{4}}HC{{O}_{3}}\xrightarrow{\,}\,NaHC{{O}_{3}}+N{{H}_{4}}C\ell \]\[NaC\ell +N{{H}_{4}}HC{{O}_{3}}\xrightarrow{\,}\,NaHC{{O}_{3}}+N{{H}_{4}}C\ell \]\[2NaHC{{O}_{3}}\xrightarrow{{{150}^{0}}C}\,N{{a}_{2}}C{{O}_{3}}+C{{O}_{2}}\,+{{H}_{2}}O\] \[2N{{H}_{4}}C\ell \,+Ca{{(OH)}_{2}}\,\xrightarrow{\,}\,2N{{H}_{3}}+{{H}_{2}}O\,+CaC{{\ell }_{3}}\](byproduct)


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